Integrand size = 31, antiderivative size = 62 \[ \int \frac {\sec ^2(c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^3} \, dx=-\frac {3 \text {arctanh}(\sin (c+d x))}{a^3 d}+\frac {4 i \cos (c+d x)}{a^3 d}+\frac {i \sec (c+d x)}{a^3 d}+\frac {4 \sin (c+d x)}{a^3 d} \]
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Time = 0.18 (sec) , antiderivative size = 62, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.290, Rules used = {3171, 3169, 2717, 2718, 2672, 327, 212, 2670, 14} \[ \int \frac {\sec ^2(c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^3} \, dx=-\frac {3 \text {arctanh}(\sin (c+d x))}{a^3 d}+\frac {4 \sin (c+d x)}{a^3 d}+\frac {4 i \cos (c+d x)}{a^3 d}+\frac {i \sec (c+d x)}{a^3 d} \]
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Rule 14
Rule 212
Rule 327
Rule 2670
Rule 2672
Rule 2717
Rule 2718
Rule 3169
Rule 3171
Rubi steps \begin{align*} \text {integral}& = \frac {i \int \sec ^2(c+d x) (i a \cos (c+d x)+a \sin (c+d x))^3 \, dx}{a^6} \\ & = \frac {i \int \left (-i a^3 \cos (c+d x)-3 a^3 \sin (c+d x)+3 i a^3 \sin (c+d x) \tan (c+d x)+a^3 \sin (c+d x) \tan ^2(c+d x)\right ) \, dx}{a^6} \\ & = \frac {i \int \sin (c+d x) \tan ^2(c+d x) \, dx}{a^3}-\frac {(3 i) \int \sin (c+d x) \, dx}{a^3}+\frac {\int \cos (c+d x) \, dx}{a^3}-\frac {3 \int \sin (c+d x) \tan (c+d x) \, dx}{a^3} \\ & = \frac {3 i \cos (c+d x)}{a^3 d}+\frac {\sin (c+d x)}{a^3 d}-\frac {i \text {Subst}\left (\int \frac {1-x^2}{x^2} \, dx,x,\cos (c+d x)\right )}{a^3 d}-\frac {3 \text {Subst}\left (\int \frac {x^2}{1-x^2} \, dx,x,\sin (c+d x)\right )}{a^3 d} \\ & = \frac {3 i \cos (c+d x)}{a^3 d}+\frac {4 \sin (c+d x)}{a^3 d}-\frac {i \text {Subst}\left (\int \left (-1+\frac {1}{x^2}\right ) \, dx,x,\cos (c+d x)\right )}{a^3 d}-\frac {3 \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\sin (c+d x)\right )}{a^3 d} \\ & = -\frac {3 \text {arctanh}(\sin (c+d x))}{a^3 d}+\frac {4 i \cos (c+d x)}{a^3 d}+\frac {i \sec (c+d x)}{a^3 d}+\frac {4 \sin (c+d x)}{a^3 d} \\ \end{align*}
Time = 0.45 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.76 \[ \int \frac {\sec ^2(c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^3} \, dx=-\frac {i \sec ^3(c+d x) (\cos (d x)+i \sin (d x))^3 \left (6 \text {arctanh}\left (\sin (c)+\cos (c) \tan \left (\frac {d x}{2}\right )\right ) (\cos (3 c)+i \sin (3 c))+(\cos (2 c-d x)+i \sin (2 c-d x)) (-5 i+\tan (c+d x))\right )}{a^3 d (-i+\tan (c+d x))^3} \]
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Time = 0.77 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.39
method | result | size |
derivativedivides | \(\frac {\frac {8}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-i}+\frac {2 i}{2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2}-3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )-\frac {i}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1}+3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{d \,a^{3}}\) | \(86\) |
default | \(\frac {\frac {8}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-i}+\frac {2 i}{2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2}-3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )-\frac {i}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1}+3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{d \,a^{3}}\) | \(86\) |
risch | \(\frac {4 i {\mathrm e}^{-i \left (d x +c \right )}}{d \,a^{3}}+\frac {2 i {\mathrm e}^{i \left (d x +c \right )}}{d \,a^{3} \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}+\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{d \,a^{3}}-\frac {3 \ln \left (i+{\mathrm e}^{i \left (d x +c \right )}\right )}{d \,a^{3}}\) | \(93\) |
norman | \(\frac {-\frac {8 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{a d}+\frac {8 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{a d}-\frac {10 i}{a d}+\frac {6 i \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{a d}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right ) \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right ) a^{2}}+\frac {3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{d \,a^{3}}-\frac {3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{d \,a^{3}}\) | \(142\) |
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Time = 0.25 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.81 \[ \int \frac {\sec ^2(c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^3} \, dx=-\frac {3 \, {\left (e^{\left (3 i \, d x + 3 i \, c\right )} + e^{\left (i \, d x + i \, c\right )}\right )} \log \left (e^{\left (i \, d x + i \, c\right )} + i\right ) - 3 \, {\left (e^{\left (3 i \, d x + 3 i \, c\right )} + e^{\left (i \, d x + i \, c\right )}\right )} \log \left (e^{\left (i \, d x + i \, c\right )} - i\right ) - 6 i \, e^{\left (2 i \, d x + 2 i \, c\right )} - 4 i}{a^{3} d e^{\left (3 i \, d x + 3 i \, c\right )} + a^{3} d e^{\left (i \, d x + i \, c\right )}} \]
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\[ \int \frac {\sec ^2(c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^3} \, dx=\frac {\int \frac {\sec ^{2}{\left (c + d x \right )}}{- i \sin ^{3}{\left (c + d x \right )} - 3 \sin ^{2}{\left (c + d x \right )} \cos {\left (c + d x \right )} + 3 i \sin {\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )} + \cos ^{3}{\left (c + d x \right )}}\, dx}{a^{3}} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 319 vs. \(2 (58) = 116\).
Time = 0.34 (sec) , antiderivative size = 319, normalized size of antiderivative = 5.15 \[ \int \frac {\sec ^2(c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^3} \, dx=\frac {6 \, {\left (\cos \left (3 \, d x + 3 \, c\right ) + \cos \left (d x + c\right ) + i \, \sin \left (3 \, d x + 3 \, c\right ) + i \, \sin \left (d x + c\right )\right )} \arctan \left (\cos \left (d x + c\right ), \sin \left (d x + c\right ) + 1\right ) + 6 \, {\left (\cos \left (3 \, d x + 3 \, c\right ) + \cos \left (d x + c\right ) + i \, \sin \left (3 \, d x + 3 \, c\right ) + i \, \sin \left (d x + c\right )\right )} \arctan \left (\cos \left (d x + c\right ), -\sin \left (d x + c\right ) + 1\right ) + 3 \, {\left (i \, \cos \left (3 \, d x + 3 \, c\right ) + i \, \cos \left (d x + c\right ) - \sin \left (3 \, d x + 3 \, c\right ) - \sin \left (d x + c\right )\right )} \log \left (\cos \left (d x + c\right )^{2} + \sin \left (d x + c\right )^{2} + 2 \, \sin \left (d x + c\right ) + 1\right ) + 3 \, {\left (-i \, \cos \left (3 \, d x + 3 \, c\right ) - i \, \cos \left (d x + c\right ) + \sin \left (3 \, d x + 3 \, c\right ) + \sin \left (d x + c\right )\right )} \log \left (\cos \left (d x + c\right )^{2} + \sin \left (d x + c\right )^{2} - 2 \, \sin \left (d x + c\right ) + 1\right ) + 12 \, \cos \left (2 \, d x + 2 \, c\right ) + 12 i \, \sin \left (2 \, d x + 2 \, c\right ) + 8}{-2 \, {\left (i \, a^{3} \cos \left (3 \, d x + 3 \, c\right ) + i \, a^{3} \cos \left (d x + c\right ) - a^{3} \sin \left (3 \, d x + 3 \, c\right ) - a^{3} \sin \left (d x + c\right )\right )} d} \]
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Time = 0.32 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.77 \[ \int \frac {\sec ^2(c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^3} \, dx=-\frac {\frac {3 \, \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}{a^{3}} - \frac {3 \, \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right )}{a^{3}} - \frac {2 \, {\left (4 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - i \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 5\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - i \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + i\right )} a^{3}}}{d} \]
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Time = 23.08 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.69 \[ \int \frac {\sec ^2(c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^3} \, dx=-\frac {6\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{a^3\,d}-\frac {\frac {2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{a^3}+\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,8{}\mathrm {i}}{a^3}-\frac {10{}\mathrm {i}}{a^3}}{d\,\left (-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,1{}\mathrm {i}-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,1{}\mathrm {i}+1\right )} \]
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